C++实现对八进制字符串转换为整数的代码

 #include <iostream>

inline bool IsOctNum(char c)
{
    return !(c<'0'||c>'8');
}

inline int OctToDec(const char * oct_str)
{
    int len=strlen(oct_str);
    int rtn=IsOctNum(oct_str[0])?oct_str[0]-'0':-1;
    for(int i=1;i<len&&rtn>-1;++i)
        if(IsOctNum(oct_str[i]))
            rtn=(rtn<<3)|(oct_str[i]-'0');
        else
            break;
    return rtn;
}

int main(int argc, char * argv[])
{
    char octs[]="0777";
    std::cout<<OctToDec(argv[1])<<std::endl;
    return 0;