此问题经常被人问，本文列出将文字和图片上传到数据库的方法。包括Access数据库和SQL Server数据库。
Access数据库代码
<%@ Page Language="C#" EnableViewState="true" %>
<%@ Import Namespace="System.Data.OleDb" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<script runat="server">
protected void Button1_Click( object sender, EventArgs e )
{
System.IO.Stream fileDataStream = FileUpload1.PostedFile.InputStream;
if (fileDataStream.Length < 1)
{
Msg.Text = "请选择文件。";
return;
}
//得到文件大小
int fileLength = FileUpload1.PostedFile.ContentLength;
//创建数组
byte[] fileData = new byte[fileLength];
//把文件流填充到数组
fileDataStream.Read(fileData, 0, fileLength);
//得到文件类型
string fileType = FileUpload1.PostedFile.ContentType;
//构建数据库连接，SQL语句，创建参数
string strCnn = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Server.MapPath("Image2Access.mdb");
OleDbConnection myConnection = new OleDbConnection(strCnn);
OleDbCommand command = new OleDbCommand("INSERT INTO Person (PersonName,PersonEmail,PersonSex,PersonImageType,PersonImage)" +
"VALUES (@PersonName,@PersonEmail,@PersonSex,@PersonImageType,@PersonImage)", myConnection);
command.Parameters.AddWithValue("@PersonName",TextBox1.Text);
command.Parameters.AddWithValue("@PersonEmail", "[email protected]");
command.Parameters.AddWithValue("@paramPersonSex", "男");
command.Parameters.AddWithValue("@PersonImageType", fileType);
command.Parameters.AddWithValue("@PersonImage", fileData);
//打开连接，执行查询
myConnection.Open();
command.ExecuteNonQuery();
myConnection.Close();
Response.Redirect(Request.RawUrl);
}
protected void Page_Load( object sender, EventArgs e )
{
if (!Page.IsPostBack)
{
BindGrid();
}
}
private void BindGrid( )
{
string strCnn = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source="
+ Server.MapPath("Image2Access.mdb");
OleDbConnection myConnection = new OleDbConnection(strCnn);
OleDbCommand myCommand = new OleDbCommand("SELECT * FROM Person", myConnection);
try
{
myConnection.Open();
GridView1.DataSource = myCommand.ExecuteReader(System.Data.CommandBehavior.CloseConnection);
GridView1.DataBind();
}
catch (OleDbException SQLexc)
{
Response.Write("提取数据时出现错误：" + SQLexc.ToString());
}
}
protected string FormatURL( object strArgument )
{
return "ReadImage.aspx?id=" + strArgument.ToString();
}
</script>
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title>上传文件到数据库</title>
</head>
<body>
<form id="MengXianhui" runat="server">
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="false">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<%#Eval("PersonName") %>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<%#Eval("PersonEmail") %>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<%#Eval("PersonSex") %>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<img src="<%#FormatURL(Eval("PersonID")) %>" /></ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
<br />
<br />
姓名：<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<br />
照片：<asp:FileUpload ID="FileUpload1" runat="server" />
<asp:Button ID="btnUpload" runat="server" Text="上传" OnClick="Button1_Click"></asp:Button>
<p>
<asp:Label ID="Msg" runat="server" ForeColor="Red"></asp:Label></p>
</form>
</body>
</html>